Factor
\frac{\left(3A-4B\right)\left(3A+4B\right)}{54}
Evaluate
\frac{A^{2}}{6}-\frac{8B^{2}}{27}
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\frac{9A^{2}-16B^{2}}{54}
Factor out \frac{1}{54}.
\left(3A-4B\right)\left(3A+4B\right)
Consider 9A^{2}-16B^{2}. Rewrite 9A^{2}-16B^{2} as \left(3A\right)^{2}-\left(4B\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(3A-4B\right)\left(3A+4B\right)}{54}
Rewrite the complete factored expression.
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