Solve 2-3x/6=y/3

$$\frac { 2 - 3 x } { 6 } = \frac { y } { 3 }$$

Solve for x

$$x=\frac{2-2y}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 6,3.

$$2-3x=2y$$

Subtract 2 from both sides.

$$-3x=2y-2$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{2y-2}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{2y-2}{-3}$$

Divide -2+2y by -3.

$$x=\frac{2-2y}{3}$$

Solve for y

$$y=-\frac{3x}{2}+1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 6,3.

$$2-3x=2y$$

Swap sides so that all variable terms are on the left hand side.

$$2y=2-3x$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{2-3x}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{2-3x}{2}$$

Divide 2-3x by 2.

$$y=-\frac{3x}{2}+1$$