Solve 2-3/4/3+frac{1{x}}

$$\frac { 2 - \frac { 3 } { 4 } } { 3 + \frac { 1 } { x } }$$

Evaluate

$$\frac{5x}{4\left(3x+1\right)}$$

Short Solution Steps

Convert 2 to fraction \frac{8}{4}.

$$\frac{\frac{8}{4}-\frac{3}{4}}{3+\frac{1}{x}}$$

Since \frac{8}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{8-3}{4}}{3+\frac{1}{x}}$$

Subtract 3 from 8 to get 5.

$$\frac{\frac{5}{4}}{3+\frac{1}{x}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{x}{x}.

$$\frac{\frac{5}{4}}{\frac{3x}{x}+\frac{1}{x}}$$

Since \frac{3x}{x} and \frac{1}{x} have the same denominator, add them by adding their numerators.

$$\frac{\frac{5}{4}}{\frac{3x+1}{x}}$$

Divide \frac{5}{4} by \frac{3x+1}{x} by multiplying \frac{5}{4} by the reciprocal of \frac{3x+1}{x}.

$$\frac{5x}{4\left(3x+1\right)}$$

Use the distributive property to multiply 4 by 3x+1.

$$\frac{5x}{12x+4}$$

Expand

$$\frac{5x}{4\left(3x+1\right)}$$

Short Solution Steps

Convert 2 to fraction \frac{8}{4}.

$$\frac{\frac{8}{4}-\frac{3}{4}}{3+\frac{1}{x}}$$

Since \frac{8}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{8-3}{4}}{3+\frac{1}{x}}$$

Subtract 3 from 8 to get 5.

$$\frac{\frac{5}{4}}{3+\frac{1}{x}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{x}{x}.

$$\frac{\frac{5}{4}}{\frac{3x}{x}+\frac{1}{x}}$$

Since \frac{3x}{x} and \frac{1}{x} have the same denominator, add them by adding their numerators.

$$\frac{\frac{5}{4}}{\frac{3x+1}{x}}$$

Divide \frac{5}{4} by \frac{3x+1}{x} by multiplying \frac{5}{4} by the reciprocal of \frac{3x+1}{x}.

$$\frac{5x}{4\left(3x+1\right)}$$

Use the distributive property to multiply 4 by 3x+1.

$$\frac{5x}{12x+4}$$