Solve 2-2/1-2/2+frac{2{1+2}}=

$$\frac { 2 - \frac { 2 } { 1 - 2 } } { 2 + \frac { 2 } { 1 + 2 } } =$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Subtract 2 from 1 to get -1.

$$\frac{2-\frac{2}{-1}}{2+\frac{2}{1+2}}$$

Fraction \frac{2}{-1} can be rewritten as -2 by extracting the negative sign.

$$\frac{2-\left(-2\right)}{2+\frac{2}{1+2}}$$

The opposite of -2 is 2.

$$\frac{2+2}{2+\frac{2}{1+2}}$$

Add 2 and 2 to get 4.

$$\frac{4}{2+\frac{2}{1+2}}$$

Add 1 and 2 to get 3.

$$\frac{4}{2+\frac{2}{3}}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{4}{\frac{6}{3}+\frac{2}{3}}$$

Since \frac{6}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{4}{\frac{6+2}{3}}$$

Add 6 and 2 to get 8.

$$\frac{4}{\frac{8}{3}}$$

Divide 4 by \frac{8}{3} by multiplying 4 by the reciprocal of \frac{8}{3}.

$$4\times \frac{3}{8}$$

Express 4\times \frac{3}{8} as a single fraction.

$$\frac{4\times 3}{8}$$

Multiply 4 and 3 to get 12.

$$\frac{12}{8}$$

Reduce the fraction \frac{12}{8} to lowest terms by extracting and canceling out 4.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$