Solve 2(3)^2+11(3)-6/3(3)-3

$$\frac { 2 ( 3 ) ^ { 2 } + 11 ( 3 ) - 6 } { 3 ( 3 ) - 3 }$$

Evaluate

$$\frac{15}{2}=7.5$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\frac{2\times 9+11\times 3-6}{3\times 3-3}$$

Multiply 2 and 9 to get 18.

$$\frac{18+11\times 3-6}{3\times 3-3}$$

Multiply 11 and 3 to get 33.

$$\frac{18+33-6}{3\times 3-3}$$

Add 18 and 33 to get 51.

$$\frac{51-6}{3\times 3-3}$$

Subtract 6 from 51 to get 45.

$$\frac{45}{3\times 3-3}$$

Multiply 3 and 3 to get 9.

$$\frac{45}{9-3}$$

Subtract 3 from 9 to get 6.

$$\frac{45}{6}$$

Reduce the fraction \frac{45}{6} to lowest terms by extracting and canceling out 3.

$$\frac{15}{2}$$

Factor

$$\frac{3 \cdot 5}{2} = 7\frac{1}{2} = 7.5$$