Solve 2(2)^2-7/3(2)-5

$$\frac { 2 ( 2 ) ^ { 2 } - 7 } { 3 ( 2 ) - 5 }$$

Evaluate

$$1$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\frac{2^{3}-7}{3\times 2-5}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{8-7}{3\times 2-5}$$

Subtract 7 from 8 to get 1.

$$\frac{1}{3\times 2-5}$$

Multiply 3 and 2 to get 6.

$$\frac{1}{6-5}$$

Subtract 5 from 6 to get 1.

$$\frac{1}{1}$$

Anything divided by one gives itself.

$$1$$

Factor

$$1$$