Solve 2(12)+1/12-2=2(12)+6/12=0

$$\frac { 2 ( 12 ) + 1 } { 12 - 2 } = \frac { 2 ( 12 ) + 6 } { 12 } = 0$$

Verify

Solution Steps

Multiply 2 and 12 to get 24.

$$\frac{24+1}{12-2}=\frac{2\times 12+6}{12}\text{ and }\frac{2\times 12+6}{12}=0$$

Add 24 and 1 to get 25.

$$\frac{25}{12-2}=\frac{2\times 12+6}{12}\text{ and }\frac{2\times 12+6}{12}=0$$

Subtract 2 from 12 to get 10.

$$\frac{25}{10}=\frac{2\times 12+6}{12}\text{ and }\frac{2\times 12+6}{12}=0$$

Reduce the fraction \frac{25}{10} to lowest terms by extracting and canceling out 5.

$$\frac{5}{2}=\frac{2\times 12+6}{12}\text{ and }\frac{2\times 12+6}{12}=0$$

Multiply 2 and 12 to get 24.

$$\frac{5}{2}=\frac{24+6}{12}\text{ and }\frac{2\times 12+6}{12}=0$$

Add 24 and 6 to get 30.

$$\frac{5}{2}=\frac{30}{12}\text{ and }\frac{2\times 12+6}{12}=0$$

Reduce the fraction \frac{30}{12} to lowest terms by extracting and canceling out 6.

$$\frac{5}{2}=\frac{5}{2}\text{ and }\frac{2\times 12+6}{12}=0$$

Compare \frac{5}{2} and \frac{5}{2}.

$$\text{true}\text{ and }\frac{2\times 12+6}{12}=0$$

Multiply 2 and 12 to get 24.

$$\text{true}\text{ and }\frac{24+6}{12}=0$$

Add 24 and 6 to get 30.

$$\text{true}\text{ and }\frac{30}{12}=0$$

Reduce the fraction \frac{30}{12} to lowest terms by extracting and canceling out 6.

$$\text{true}\text{ and }\frac{5}{2}=0$$

Compare \frac{5}{2} and 0.

$$\text{true}\text{ and }\text{false}$$

The conjunction of \text{true} and \text{false} is \text{false}.

$$\text{false}$$