Solve 2(-1+3)/8(frac{1{2})^2}-3(1/2)(-2/3)/3--1+1

$$\frac { 2 ( - 1 + 3 ) } { 8 ( \frac { 1 } { 2 } ) ^ { 2 } } - \frac { 3 ( \frac { 1 } { 2 } ) ( - \frac { 2 } { 3 } ) } { 3 - - 1 + 1 }$$

Evaluate

$$\frac{11}{5}=2.2$$

Solution Steps

Cancel out 2 in both numerator and denominator.

$$\frac{3-1}{4\times \left(\frac{1}{2}\right)^{2}}-\frac{3\times \frac{1}{2}\left(-\frac{2}{3}\right)}{3-\left(-1\right)+1}$$

Subtract 1 from 3 to get 2.

$$\frac{2}{4\times \left(\frac{1}{2}\right)^{2}}-\frac{3\times \frac{1}{2}\left(-\frac{2}{3}\right)}{3-\left(-1\right)+1}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{2}{4\times \frac{1}{4}}-\frac{3\times \frac{1}{2}\left(-\frac{2}{3}\right)}{3-\left(-1\right)+1}$$

Cancel out 4 and 4.

$$\frac{2}{1}-\frac{3\times \frac{1}{2}\left(-\frac{2}{3}\right)}{3-\left(-1\right)+1}$$

Anything divided by one gives itself.

$$2-\frac{3\times \frac{1}{2}\left(-\frac{2}{3}\right)}{3-\left(-1\right)+1}$$

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$2-\frac{\frac{3}{2}\left(-\frac{2}{3}\right)}{3-\left(-1\right)+1}$$

Multiply \frac{3}{2} times -\frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$2-\frac{\frac{3\left(-2\right)}{2\times 3}}{3-\left(-1\right)+1}$$

Cancel out 3 in both numerator and denominator.

$$2-\frac{\frac{-2}{2}}{3-\left(-1\right)+1}$$

Divide -2 by 2 to get -1.

$$2-\frac{-1}{3-\left(-1\right)+1}$$

The opposite of -1 is 1.

$$2-\frac{-1}{3+1+1}$$

Add 3 and 1 to get 4.

$$2-\frac{-1}{4+1}$$

Add 4 and 1 to get 5.

$$2-\frac{-1}{5}$$

Fraction \frac{-1}{5} can be rewritten as -\frac{1}{5} by extracting the negative sign.

$$2-\left(-\frac{1}{5}\right)$$

The opposite of -\frac{1}{5} is \frac{1}{5}.

$$2+\frac{1}{5}$$

Convert 2 to fraction \frac{10}{5}.

$$\frac{10}{5}+\frac{1}{5}$$

Since \frac{10}{5} and \frac{1}{5} have the same denominator, add them by adding their numerators.

$$\frac{10+1}{5}$$

Add 10 and 1 to get 11.

$$\frac{11}{5}$$

Factor

$$\frac{11}{5} = 2\frac{1}{5} = 2.2$$