Solve 2/x-2/x+1

$$\frac { 2 } { x } - \frac { 2 } { x + 1 }$$

Evaluate

$$\frac{2}{x\left(x+1\right)}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x and x+1 is x\left(x+1\right). Multiply \frac{2}{x} times \frac{x+1}{x+1}. Multiply \frac{2}{x+1} times \frac{x}{x}.

$$\frac{2\left(x+1\right)}{x\left(x+1\right)}-\frac{2x}{x\left(x+1\right)}$$

Since \frac{2\left(x+1\right)}{x\left(x+1\right)} and \frac{2x}{x\left(x+1\right)} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2\left(x+1\right)-2x}{x\left(x+1\right)}$$

Do the multiplications in 2\left(x+1\right)-2x.

$$\frac{2x+2-2x}{x\left(x+1\right)}$$

Combine like terms in 2x+2-2x.

$$\frac{2}{x\left(x+1\right)}$$

Expand x\left(x+1\right).

$$\frac{2}{x^{2}+x}$$

Factor

$$\frac{2}{x\left(x+1\right)}$$