Solve for x
x=21
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\left(2x-3\right)\times 2=\left(x+5\right)\times 3
Variable x cannot be equal to any of the values -5,\frac{3}{2} since division by zero is not defined. Multiply both sides of the equation by \left(2x-3\right)\left(x+5\right), the least common multiple of x+5,2x-3.
4x-6=\left(x+5\right)\times 3
Use the distributive property to multiply 2x-3 by 2.
4x-6=3x+15
Use the distributive property to multiply x+5 by 3.
4x-6-3x=15
Subtract 3x from both sides.
x-6=15
Combine 4x and -3x to get x.
x=15+6
Add 6 to both sides.
x=21
Add 15 and 6 to get 21.
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