Solve for t
t=4
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2=\left(t-3\right)\times 2
Variable t cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(t-3\right)\left(t+3\right), the least common multiple of t^{2}-9,t+3.
2=2t-6
Use the distributive property to multiply t-3 by 2.
2t-6=2
Swap sides so that all variable terms are on the left hand side.
2t=2+6
Add 6 to both sides.
2t=8
Add 2 and 6 to get 8.
t=\frac{8}{2}
Divide both sides by 2.
t=4
Divide 8 by 2 to get 4.
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