Solve for n
n=9
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\left(n+1\right)\times 2=\left(n-5\right)\times 5
Variable n cannot be equal to any of the values -1,5 since division by zero is not defined. Multiply both sides of the equation by \left(n-5\right)\left(n+1\right), the least common multiple of n-5,n+1.
2n+2=\left(n-5\right)\times 5
Use the distributive property to multiply n+1 by 2.
2n+2=5n-25
Use the distributive property to multiply n-5 by 5.
2n+2-5n=-25
Subtract 5n from both sides.
-3n+2=-25
Combine 2n and -5n to get -3n.
-3n=-25-2
Subtract 2 from both sides.
-3n=-27
Subtract 2 from -25 to get -27.
n=\frac{-27}{-3}
Divide both sides by -3.
n=9
Divide -27 by -3 to get 9.
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