Solve 2/c+4-3/c^2=

$$\frac { 2 } { c } + 4 - \frac { 3 } { c ^ { 2 } } =$$

Evaluate

$$4+\frac{2}{c}-\frac{3}{c^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 4 times \frac{c}{c}.

$$\frac{2}{c}+\frac{4c}{c}-\frac{3}{c^{2}}$$

Since \frac{2}{c} and \frac{4c}{c} have the same denominator, add them by adding their numerators.

$$\frac{2+4c}{c}-\frac{3}{c^{2}}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of c and c^{2} is c^{2}. Multiply \frac{2+4c}{c} times \frac{c}{c}.

$$\frac{\left(2+4c\right)c}{c^{2}}-\frac{3}{c^{2}}$$

Since \frac{\left(2+4c\right)c}{c^{2}} and \frac{3}{c^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(2+4c\right)c-3}{c^{2}}$$

Do the multiplications in \left(2+4c\right)c-3.

$$\frac{2c+4c^{2}-3}{c^{2}}$$

Factor

$$\frac{4\left(c-\frac{-\sqrt{13}-1}{4}\right)\left(c-\frac{\sqrt{13}-1}{4}\right)}{c^{2}}$$