Solve 2/9-31/18+47/12

$$\frac { 2 } { 9 } - 3 \frac { 1 } { 18 } + 4 \frac { 7 } { 12 }$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Multiply 3 and 18 to get 54.

$$\frac{2}{9}-\frac{54+1}{18}+\frac{4\times 12+7}{12}$$

Add 54 and 1 to get 55.

$$\frac{2}{9}-\frac{55}{18}+\frac{4\times 12+7}{12}$$

Least common multiple of 9 and 18 is 18. Convert \frac{2}{9} and \frac{55}{18} to fractions with denominator 18.

$$\frac{4}{18}-\frac{55}{18}+\frac{4\times 12+7}{12}$$

Since \frac{4}{18} and \frac{55}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-55}{18}+\frac{4\times 12+7}{12}$$

Subtract 55 from 4 to get -51.

$$\frac{-51}{18}+\frac{4\times 12+7}{12}$$

Reduce the fraction \frac{-51}{18} to lowest terms by extracting and canceling out 3.

$$-\frac{17}{6}+\frac{4\times 12+7}{12}$$

Multiply 4 and 12 to get 48.

$$-\frac{17}{6}+\frac{48+7}{12}$$

Add 48 and 7 to get 55.

$$-\frac{17}{6}+\frac{55}{12}$$

Least common multiple of 6 and 12 is 12. Convert -\frac{17}{6} and \frac{55}{12} to fractions with denominator 12.

$$-\frac{34}{12}+\frac{55}{12}$$

Since -\frac{34}{12} and \frac{55}{12} have the same denominator, add them by adding their numerators.

$$\frac{-34+55}{12}$$

Add -34 and 55 to get 21.

$$\frac{21}{12}$$

Reduce the fraction \frac{21}{12} to lowest terms by extracting and canceling out 3.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$