Solve 2/9+(1/6+2/3)=

$$\frac { 2 } { 9 } + ( \frac { 1 } { 6 } + \frac { 2 } { 3 } ) =$$

Evaluate

$$\frac{19}{18}\approx 1.055555556$$

Solution Steps

Least common multiple of 9 and 6 is 18. Convert \frac{2}{9} and \frac{1}{6} to fractions with denominator 18.

$$\frac{4}{18}+\frac{3}{18}+\frac{2}{3}$$

Since \frac{4}{18} and \frac{3}{18} have the same denominator, add them by adding their numerators.

$$\frac{4+3}{18}+\frac{2}{3}$$

Add 4 and 3 to get 7.

$$\frac{7}{18}+\frac{2}{3}$$

Least common multiple of 18 and 3 is 18. Convert \frac{7}{18} and \frac{2}{3} to fractions with denominator 18.

$$\frac{7}{18}+\frac{12}{18}$$

Since \frac{7}{18} and \frac{12}{18} have the same denominator, add them by adding their numerators.

$$\frac{7+12}{18}$$

Add 7 and 12 to get 19.

$$\frac{19}{18}$$

Factor

$$\frac{19}{2 \cdot 3 ^ {2}} = 1\frac{1}{18} = 1.0555555555555556$$