Solve 2/8+ngeq7

$$\frac { 2 } { 8 } + n \geq 7$$

Solve for n

$$n\geq \frac{27}{4}$$

Solution Steps

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$\frac{1}{4}+n\geq 7$$

Subtract \frac{1}{4} from both sides.

$$n\geq 7-\frac{1}{4}$$

Convert 7 to fraction \frac{28}{4}.

$$n\geq \frac{28}{4}-\frac{1}{4}$$

Since \frac{28}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$n\geq \frac{28-1}{4}$$

Subtract 1 from 28 to get 27.

$$n\geq \frac{27}{4}$$