Solve 2/7*8/20*4/16*21/3

$$\frac { 2 } { 7 } \cdot \frac { 8 } { 20 } \cdot \frac { 4 } { 16 } \cdot \frac { 21 } { 3 }$$

Evaluate

$$\frac{1}{5}=0.2$$

Solution Steps

Reduce the fraction \frac{8}{20} to lowest terms by extracting and canceling out 4.

$$\frac{2}{7}\times \frac{2}{5}\times \frac{4}{16}\times \frac{21}{3}$$

Multiply \frac{2}{7} times \frac{2}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 2}{7\times 5}\times \frac{4}{16}\times \frac{21}{3}$$

Do the multiplications in the fraction \frac{2\times 2}{7\times 5}.

$$\frac{4}{35}\times \frac{4}{16}\times \frac{21}{3}$$

Reduce the fraction \frac{4}{16} to lowest terms by extracting and canceling out 4.

$$\frac{4}{35}\times \frac{1}{4}\times \frac{21}{3}$$

Multiply \frac{4}{35} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\times 1}{35\times 4}\times \frac{21}{3}$$

Cancel out 4 in both numerator and denominator.

$$\frac{1}{35}\times \frac{21}{3}$$

Divide 21 by 3 to get 7.

$$\frac{1}{35}\times 7$$

Multiply \frac{1}{35} and 7 to get \frac{7}{35}.

$$\frac{7}{35}$$

Reduce the fraction \frac{7}{35} to lowest terms by extracting and canceling out 7.

$$\frac{1}{5}$$

Factor

$$\frac{1}{5} = 0.2$$