Solve 2/7*14/5:49/15-5/49

$$\frac { 2 } { 7 } \cdot \frac { 14 } { 5 } : \frac { 49 } { 15 } - \frac { 5 } { 49 }$$

Evaluate

$$\frac{1}{7}\approx 0.142857143$$

Solution Steps

Multiply \frac{2}{7} times \frac{14}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{2\times 14}{7\times 5}}{\frac{49}{15}}-\frac{5}{49}$$

Do the multiplications in the fraction \frac{2\times 14}{7\times 5}.

$$\frac{\frac{28}{35}}{\frac{49}{15}}-\frac{5}{49}$$

Reduce the fraction \frac{28}{35} to lowest terms by extracting and canceling out 7.

$$\frac{\frac{4}{5}}{\frac{49}{15}}-\frac{5}{49}$$

Divide \frac{4}{5} by \frac{49}{15} by multiplying \frac{4}{5} by the reciprocal of \frac{49}{15}.

$$\frac{4}{5}\times \frac{15}{49}-\frac{5}{49}$$

Multiply \frac{4}{5} times \frac{15}{49} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\times 15}{5\times 49}-\frac{5}{49}$$

Do the multiplications in the fraction \frac{4\times 15}{5\times 49}.

$$\frac{60}{245}-\frac{5}{49}$$

Reduce the fraction \frac{60}{245} to lowest terms by extracting and canceling out 5.

$$\frac{12}{49}-\frac{5}{49}$$

Since \frac{12}{49} and \frac{5}{49} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12-5}{49}$$

Subtract 5 from 12 to get 7.

$$\frac{7}{49}$$

Reduce the fraction \frac{7}{49} to lowest terms by extracting and canceling out 7.

$$\frac{1}{7}$$

Factor

$$\frac{1}{7} = 0.14285714285714285$$