Solve 2/7+3/14=1/8+21/56

$$\frac { 2 } { 7 } + \frac { 3 } { 14 } = \frac { 1 } { 8 } + \frac { 21 } { 56 }$$

Verify

Solution Steps

Least common multiple of 7 and 14 is 14. Convert \frac{2}{7} and \frac{3}{14} to fractions with denominator 14.

$$\frac{4}{14}+\frac{3}{14}=\frac{1}{8}+\frac{21}{56}$$

Since \frac{4}{14} and \frac{3}{14} have the same denominator, add them by adding their numerators.

$$\frac{4+3}{14}=\frac{1}{8}+\frac{21}{56}$$

Add 4 and 3 to get 7.

$$\frac{7}{14}=\frac{1}{8}+\frac{21}{56}$$

Reduce the fraction \frac{7}{14} to lowest terms by extracting and canceling out 7.

$$\frac{1}{2}=\frac{1}{8}+\frac{21}{56}$$

Reduce the fraction \frac{21}{56} to lowest terms by extracting and canceling out 7.

$$\frac{1}{2}=\frac{1}{8}+\frac{3}{8}$$

Since \frac{1}{8} and \frac{3}{8} have the same denominator, add them by adding their numerators.

$$\frac{1}{2}=\frac{1+3}{8}$$

Add 1 and 3 to get 4.

$$\frac{1}{2}=\frac{4}{8}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$\frac{1}{2}=\frac{1}{2}$$

Compare \frac{1}{2} and \frac{1}{2}.

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