Solve 2/5a^2+1/3ab=

$$\frac { 2 } { 5 a ^ { 2 } } + \frac { 1 } { 3 a b } =$$

Evaluate

$$\frac{1}{3ab}+\frac{2}{5a^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 5a^{2} and 3ab is 15ba^{2}. Multiply \frac{2}{5a^{2}} times \frac{3b}{3b}. Multiply \frac{1}{3ab} times \frac{5a}{5a}.

$$\frac{2\times 3b}{15ba^{2}}+\frac{5a}{15ba^{2}}$$

Since \frac{2\times 3b}{15ba^{2}} and \frac{5a}{15ba^{2}} have the same denominator, add them by adding their numerators.

$$\frac{2\times 3b+5a}{15ba^{2}}$$

Do the multiplications in 2\times 3b+5a.

$$\frac{6b+5a}{15ba^{2}}$$

Factor

$$\frac{\left(\frac{5a}{b}+6\right)\times \left(\frac{1}{a}\right)^{2}}{15}$$