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x^{2}=9\times \frac{5}{2}
Multiply both sides by \frac{5}{2}, the reciprocal of \frac{2}{5}.
x^{2}=\frac{45}{2}
Multiply 9 and \frac{5}{2} to get \frac{45}{2}.
x=\frac{3\sqrt{10}}{2} x=-\frac{3\sqrt{10}}{2}
Take the square root of both sides of the equation.
x^{2}=9\times \frac{5}{2}
Multiply both sides by \frac{5}{2}, the reciprocal of \frac{2}{5}.
x^{2}=\frac{45}{2}
Multiply 9 and \frac{5}{2} to get \frac{45}{2}.
x^{2}-\frac{45}{2}=0
Subtract \frac{45}{2} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{45}{2}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{45}{2} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{45}{2}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{90}}{2}
Multiply -4 times -\frac{45}{2}.
x=\frac{0±3\sqrt{10}}{2}
Take the square root of 90.
x=\frac{3\sqrt{10}}{2}
Now solve the equation x=\frac{0±3\sqrt{10}}{2} when ± is plus.
x=-\frac{3\sqrt{10}}{2}
Now solve the equation x=\frac{0±3\sqrt{10}}{2} when ± is minus.
x=\frac{3\sqrt{10}}{2} x=-\frac{3\sqrt{10}}{2}
The equation is now solved.