Solve for x
x=-2
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Quiz
Linear Equation
\frac { 2 } { 5 } x + \frac { 3 } { 5 } = - \frac { 3 } { 5 } - \frac { 1 } { 5 } x
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\frac{2}{5}x+\frac{3}{5}+\frac{1}{5}x=-\frac{3}{5}
Add \frac{1}{5}x to both sides.
\frac{3}{5}x+\frac{3}{5}=-\frac{3}{5}
Combine \frac{2}{5}x and \frac{1}{5}x to get \frac{3}{5}x.
\frac{3}{5}x=-\frac{3}{5}-\frac{3}{5}
Subtract \frac{3}{5} from both sides.
\frac{3}{5}x=\frac{-3-3}{5}
Since -\frac{3}{5} and \frac{3}{5} have the same denominator, subtract them by subtracting their numerators.
\frac{3}{5}x=-\frac{6}{5}
Subtract 3 from -3 to get -6.
x=-\frac{6}{5}\times \frac{5}{3}
Multiply both sides by \frac{5}{3}, the reciprocal of \frac{3}{5}.
x=\frac{-6\times 5}{5\times 3}
Multiply -\frac{6}{5} times \frac{5}{3} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-6}{3}
Cancel out 5 in both numerator and denominator.
x=-2
Divide -6 by 3 to get -2.
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}