Solve 2/5=3/DC

$$\frac { 2 } { 5 } = \frac { 3 } { D C }$$

Solve for C

$$C=\frac{15}{2D}$$

$$D\neq 0$$

Steps for Solving Linear Equation

Variable C cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 5CD, the least common multiple of 5,DC.

$$2CD=5\times 3$$

Multiply 5 and 3 to get 15.

$$2CD=15$$

The equation is in standard form.

$$2DC=15$$

Divide both sides by 2D.

$$\frac{2DC}{2D}=\frac{15}{2D}$$

Dividing by 2D undoes the multiplication by 2D.

$$C=\frac{15}{2D}$$

Variable C cannot be equal to 0.

$$C=\frac{15}{2D}\text{, }C\neq 0$$

Solve for D

$$D=\frac{15}{2C}$$

$$C\neq 0$$

Steps for Solving Linear Equation

Variable D cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 5CD, the least common multiple of 5,DC.

$$2CD=5\times 3$$

Multiply 5 and 3 to get 15.

$$2CD=15$$

Divide both sides by 2C.

$$\frac{2CD}{2C}=\frac{15}{2C}$$

Dividing by 2C undoes the multiplication by 2C.

$$D=\frac{15}{2C}$$

Variable D cannot be equal to 0.

$$D=\frac{15}{2C}\text{, }D\neq 0$$