Solve 2/5+4/3*3/5-(1/4)^2=

$$\frac { 2 } { 5 } + \frac { 4 } { 3 } \cdot \frac { 3 } { 5 } - ( \frac { 1 } { 4 } ) ^ { 2 } =$$

Evaluate

$$\frac{91}{80}=1.1375$$

Solution Steps

Multiply \frac{4}{3} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2}{5}+\frac{4\times 3}{3\times 5}-\left(\frac{1}{4}\right)^{2}$$

Cancel out 3 in both numerator and denominator.

$$\frac{2}{5}+\frac{4}{5}-\left(\frac{1}{4}\right)^{2}$$

Since \frac{2}{5} and \frac{4}{5} have the same denominator, add them by adding their numerators.

$$\frac{2+4}{5}-\left(\frac{1}{4}\right)^{2}$$

Add 2 and 4 to get 6.

$$\frac{6}{5}-\left(\frac{1}{4}\right)^{2}$$

Calculate \frac{1}{4} to the power of 2 and get \frac{1}{16}.

$$\frac{6}{5}-\frac{1}{16}$$

Least common multiple of 5 and 16 is 80. Convert \frac{6}{5} and \frac{1}{16} to fractions with denominator 80.

$$\frac{96}{80}-\frac{5}{80}$$

Since \frac{96}{80} and \frac{5}{80} have the same denominator, subtract them by subtracting their numerators.

$$\frac{96-5}{80}$$

Subtract 5 from 96 to get 91.

$$\frac{91}{80}$$

Factor

$$\frac{7 \cdot 13}{2 ^ {4} \cdot 5} = 1\frac{11}{80} = 1.1375$$