Solve 2/49z^3y-1/14z^2y

$$\frac { 2 } { 49 z ^ { 3 } y } - \frac { 1 } { 14 z ^ { 2 } y }$$

Evaluate

$$-\frac{7z-4}{98yz^{3}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 49z^{3}y and 14z^{2}y is 98yz^{3}. Multiply \frac{2}{49z^{3}y} times \frac{2}{2}. Multiply \frac{1}{14z^{2}y} times \frac{7z}{7z}.

$$\frac{2\times 2}{98yz^{3}}-\frac{7z}{98yz^{3}}$$

Since \frac{2\times 2}{98yz^{3}} and \frac{7z}{98yz^{3}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2\times 2-7z}{98yz^{3}}$$

Do the multiplications in 2\times 2-7z.

$$\frac{4-7z}{98yz^{3}}$$

Factor

$$-\frac{7z-4}{98yz^{3}}$$