Solve 2/45+(3/45+7/9)

$$\frac { 2 } { 45 } + ( \frac { 3 } { 45 } + \frac { 7 } { 9 } )$$

Evaluate

$$\frac{8}{9}\approx 0.888888889$$

Solution Steps

Since \frac{2}{45} and \frac{3}{45} have the same denominator, add them by adding their numerators.

$$\frac{2+3}{45}+\frac{7}{9}$$

Add 2 and 3 to get 5.

$$\frac{5}{45}+\frac{7}{9}$$

Reduce the fraction \frac{5}{45} to lowest terms by extracting and canceling out 5.

$$\frac{1}{9}+\frac{7}{9}$$

Since \frac{1}{9} and \frac{7}{9} have the same denominator, add them by adding their numerators.

$$\frac{1+7}{9}$$

Add 1 and 7 to get 8.

$$\frac{8}{9}$$

Factor

$$\frac{2 ^ {3}}{3 ^ {2}} = 0.8888888888888888$$