Solve 2/40+7/80-11/36-13/72

$$\frac { 2 } { 40 } + \frac { 7 } { 80 } - \frac { 11 } { 36 } - \frac { 13 } { 72 }$$

Evaluate

$$-\frac{251}{720}\approx -0.348611111$$

Solution Steps

Reduce the fraction \frac{2}{40} to lowest terms by extracting and canceling out 2.

$$\frac{1}{20}+\frac{7}{80}-\frac{11}{36}-\frac{13}{72}$$

Least common multiple of 20 and 80 is 80. Convert \frac{1}{20} and \frac{7}{80} to fractions with denominator 80.

$$\frac{4}{80}+\frac{7}{80}-\frac{11}{36}-\frac{13}{72}$$

Since \frac{4}{80} and \frac{7}{80} have the same denominator, add them by adding their numerators.

$$\frac{4+7}{80}-\frac{11}{36}-\frac{13}{72}$$

Add 4 and 7 to get 11.

$$\frac{11}{80}-\frac{11}{36}-\frac{13}{72}$$

Least common multiple of 80 and 36 is 720. Convert \frac{11}{80} and \frac{11}{36} to fractions with denominator 720.

$$\frac{99}{720}-\frac{220}{720}-\frac{13}{72}$$

Since \frac{99}{720} and \frac{220}{720} have the same denominator, subtract them by subtracting their numerators.

$$\frac{99-220}{720}-\frac{13}{72}$$

Subtract 220 from 99 to get -121.

$$-\frac{121}{720}-\frac{13}{72}$$

Least common multiple of 720 and 72 is 720. Convert -\frac{121}{720} and \frac{13}{72} to fractions with denominator 720.

$$-\frac{121}{720}-\frac{130}{720}$$

Since -\frac{121}{720} and \frac{130}{720} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-121-130}{720}$$

Subtract 130 from -121 to get -251.

$$-\frac{251}{720}$$

Factor

$$-\frac{251}{720} = -0.3486111111111111$$