Solve 2/40+7/80-11/26+13/72

$$\frac { 2 } { 40 } + \frac { 7 } { 80 } - \frac { 11 } { 26 } + \frac { 13 } { 72 }$$

Evaluate

$$-\frac{983}{9360}\approx -0.105021368$$

Solution Steps

Reduce the fraction \frac{2}{40} to lowest terms by extracting and canceling out 2.

$$\frac{1}{20}+\frac{7}{80}-\frac{11}{26}+\frac{13}{72}$$

Least common multiple of 20 and 80 is 80. Convert \frac{1}{20} and \frac{7}{80} to fractions with denominator 80.

$$\frac{4}{80}+\frac{7}{80}-\frac{11}{26}+\frac{13}{72}$$

Since \frac{4}{80} and \frac{7}{80} have the same denominator, add them by adding their numerators.

$$\frac{4+7}{80}-\frac{11}{26}+\frac{13}{72}$$

Add 4 and 7 to get 11.

$$\frac{11}{80}-\frac{11}{26}+\frac{13}{72}$$

Least common multiple of 80 and 26 is 1040. Convert \frac{11}{80} and \frac{11}{26} to fractions with denominator 1040.

$$\frac{143}{1040}-\frac{440}{1040}+\frac{13}{72}$$

Since \frac{143}{1040} and \frac{440}{1040} have the same denominator, subtract them by subtracting their numerators.

$$\frac{143-440}{1040}+\frac{13}{72}$$

Subtract 440 from 143 to get -297.

$$-\frac{297}{1040}+\frac{13}{72}$$

Least common multiple of 1040 and 72 is 9360. Convert -\frac{297}{1040} and \frac{13}{72} to fractions with denominator 9360.

$$-\frac{2673}{9360}+\frac{1690}{9360}$$

Since -\frac{2673}{9360} and \frac{1690}{9360} have the same denominator, add them by adding their numerators.

$$\frac{-2673+1690}{9360}$$

Add -2673 and 1690 to get -983.

$$-\frac{983}{9360}$$

Factor

$$-\frac{983}{9360} = -0.10502136752136752$$