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20\times 2+20\left(3x-4\right)\left(-\frac{1}{20}\right)=10\times 5
Variable x cannot be equal to \frac{4}{3} since division by zero is not defined. Multiply both sides of the equation by 20\left(3x-4\right), the least common multiple of 3x-4,20,6x-8.
40+20\left(3x-4\right)\left(-\frac{1}{20}\right)=10\times 5
Multiply 20 and 2 to get 40.
40-\left(3x-4\right)=10\times 5
Multiply 20 and -\frac{1}{20} to get -1.
40-3x+4=10\times 5
To find the opposite of 3x-4, find the opposite of each term.
44-3x=10\times 5
Add 40 and 4 to get 44.
44-3x=50
Multiply 10 and 5 to get 50.
-3x=50-44
Subtract 44 from both sides.
-3x=6
Subtract 44 from 50 to get 6.
x=\frac{6}{-3}
Divide both sides by -3.
x=-2
Divide 6 by -3 to get -2.