Solve for y
y=12
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10y-3\left(2\times 5+2\right)=3\left(5\times 5+3\right)
Multiply both sides of the equation by 15, the least common multiple of 3,5.
10y-3\left(10+2\right)=3\left(5\times 5+3\right)
Multiply 2 and 5 to get 10.
10y-3\times 12=3\left(5\times 5+3\right)
Add 10 and 2 to get 12.
10y-36=3\left(5\times 5+3\right)
Multiply -3 and 12 to get -36.
10y-36=3\left(25+3\right)
Multiply 5 and 5 to get 25.
10y-36=3\times 28
Add 25 and 3 to get 28.
10y-36=84
Multiply 3 and 28 to get 84.
10y=84+36
Add 36 to both sides.
10y=120
Add 84 and 36 to get 120.
y=\frac{120}{10}
Divide both sides by 10.
y=12
Divide 120 by 10 to get 12.
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