Solve 2/3x+4/3=1/3x+7

$$\frac { 2 } { 3 } x + \frac { 4 } { 3 } = \frac { 1 } { 3 } x + 7$$

Solve for x

$$x=17$$

Steps for Solving Linear Equation

Subtract \frac{1}{3}x from both sides.

$$\frac{2}{3}x+\frac{4}{3}-\frac{1}{3}x=7$$

Combine \frac{2}{3}x and -\frac{1}{3}x to get \frac{1}{3}x.

$$\frac{1}{3}x+\frac{4}{3}=7$$

Subtract \frac{4}{3} from both sides.

$$\frac{1}{3}x=7-\frac{4}{3}$$

Convert 7 to fraction \frac{21}{3}.

$$\frac{1}{3}x=\frac{21}{3}-\frac{4}{3}$$

Since \frac{21}{3} and \frac{4}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{3}x=\frac{21-4}{3}$$

Subtract 4 from 21 to get 17.

$$\frac{1}{3}x=\frac{17}{3}$$

Multiply both sides by 3, the reciprocal of \frac{1}{3}.

$$x=\frac{17}{3}\times 3$$

Cancel out 3 and 3.

$$x=17$$