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\frac{2}{3}x+\frac{1}{9}-\frac{1}{9}x=\frac{1}{3}
Subtract \frac{1}{9}x from both sides.
\frac{5}{9}x+\frac{1}{9}=\frac{1}{3}
Combine \frac{2}{3}x and -\frac{1}{9}x to get \frac{5}{9}x.
\frac{5}{9}x=\frac{1}{3}-\frac{1}{9}
Subtract \frac{1}{9} from both sides.
\frac{5}{9}x=\frac{3}{9}-\frac{1}{9}
Least common multiple of 3 and 9 is 9. Convert \frac{1}{3} and \frac{1}{9} to fractions with denominator 9.
\frac{5}{9}x=\frac{3-1}{9}
Since \frac{3}{9} and \frac{1}{9} have the same denominator, subtract them by subtracting their numerators.
\frac{5}{9}x=\frac{2}{9}
Subtract 1 from 3 to get 2.
x=\frac{2}{9}\times \frac{9}{5}
Multiply both sides by \frac{9}{5}, the reciprocal of \frac{5}{9}.
x=\frac{2\times 9}{9\times 5}
Multiply \frac{2}{9} times \frac{9}{5} by multiplying numerator times numerator and denominator times denominator.
x=\frac{2}{5}
Cancel out 9 in both numerator and denominator.