Solve 2/3x+1/3*2/4x+10=x

$$\frac { 2 } { 3 } x + \frac { 1 } { 3 } \cdot \frac { 2 } { 4 } x + 10 = x$$

Solve for x

$$x=60$$

Steps for Solving Linear Equation

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{2}{3}x+\frac{1}{3}\times \frac{1}{2}x+10=x$$

Multiply \frac{1}{3} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2}{3}x+\frac{1\times 1}{3\times 2}x+10=x$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 2}.

$$\frac{2}{3}x+\frac{1}{6}x+10=x$$

Combine \frac{2}{3}x and \frac{1}{6}x to get \frac{5}{6}x.

$$\frac{5}{6}x+10=x$$

Subtract x from both sides.

$$\frac{5}{6}x+10-x=0$$

Combine \frac{5}{6}x and -x to get -\frac{1}{6}x.

$$-\frac{1}{6}x+10=0$$

Subtract 10 from both sides. Anything subtracted from zero gives its negation.

$$-\frac{1}{6}x=-10$$

Multiply both sides by -6, the reciprocal of -\frac{1}{6}.

$$x=-10\left(-6\right)$$

Multiply -10 and -6 to get 60.

$$x=60$$