Solve 2/3a^{2}b^{3}x-5/3a^{2}b^{3}x+a^2b^3x)*(3/4a^2-2a^2)

$$\frac { 2 } { 3 } a ^ { 2 } b ^ { 3 } x - \frac { 5 } { 3 } a ^ { 2 } b ^ { 3 } x + a ^ { 2 } b ^ { 3 } x ) \cdot ( \frac { 3 } { 4 } a ^ { 2 } - 2 a ^ { 2 } )$$

Evaluate

$$0$$

Solution Steps

Combine \frac{2}{3}a^{2}b^{3}x and -\frac{5}{3}a^{2}b^{3}x to get -a^{2}b^{3}x.

$$-a^{2}b^{3}x+a^{2}b^{3}x$$

Combine -a^{2}b^{3}x and a^{2}b^{3}x to get 0.

$$0$$

Factor

$$0$$

Solution Steps

Factor out \frac{1}{3}.

$$\frac{2a^{2}b^{3}x-5a^{2}b^{3}x+3a^{2}b^{3}x}{3}$$

Consider 2a^{2}b^{3}x-5a^{2}b^{3}x+3a^{2}b^{3}x. Factor out a^{2}b^{3}x.

$$0$$

Rewrite the complete factored expression.

$$\frac{0}{3}$$