Solve 2/3-23-4-5-23^34^2+10

$$\frac { 2 } { 3 } - 23 - 4 - 5 - 23 ^ { 3 } 4 ^ { 2 } + 10$$

Evaluate

$$-\frac{584080}{3}\approx -194693.333333333$$

Solution Steps

Convert 23 to fraction \frac{69}{3}.

$$\frac{2}{3}-\frac{69}{3}-4-5-23^{3}\times 4^{2}+10$$

Since \frac{2}{3} and \frac{69}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-69}{3}-4-5-23^{3}\times 4^{2}+10$$

Subtract 69 from 2 to get -67.

$$-\frac{67}{3}-4-5-23^{3}\times 4^{2}+10$$

Convert 4 to fraction \frac{12}{3}.

$$-\frac{67}{3}-\frac{12}{3}-5-23^{3}\times 4^{2}+10$$

Since -\frac{67}{3} and \frac{12}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-67-12}{3}-5-23^{3}\times 4^{2}+10$$

Subtract 12 from -67 to get -79.

$$-\frac{79}{3}-5-23^{3}\times 4^{2}+10$$

Convert 5 to fraction \frac{15}{3}.

$$-\frac{79}{3}-\frac{15}{3}-23^{3}\times 4^{2}+10$$

Since -\frac{79}{3} and \frac{15}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-79-15}{3}-23^{3}\times 4^{2}+10$$

Subtract 15 from -79 to get -94.

$$-\frac{94}{3}-23^{3}\times 4^{2}+10$$

Calculate 23 to the power of 3 and get 12167.

$$-\frac{94}{3}-12167\times 4^{2}+10$$

Calculate 4 to the power of 2 and get 16.

$$-\frac{94}{3}-12167\times 16+10$$

Multiply 12167 and 16 to get 194672.

$$-\frac{94}{3}-194672+10$$

Convert 194672 to fraction \frac{584016}{3}.

$$-\frac{94}{3}-\frac{584016}{3}+10$$

Since -\frac{94}{3} and \frac{584016}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-94-584016}{3}+10$$

Subtract 584016 from -94 to get -584110.

$$-\frac{584110}{3}+10$$

Convert 10 to fraction \frac{30}{3}.

$$-\frac{584110}{3}+\frac{30}{3}$$

Since -\frac{584110}{3} and \frac{30}{3} have the same denominator, add them by adding their numerators.

$$\frac{-584110+30}{3}$$

Add -584110 and 30 to get -584080.

$$-\frac{584080}{3}$$

Factor

$$-\frac{584080}{3} = -194693\frac{1}{3} = -194693.33333333334$$