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\frac{2}{3}x+\frac{2}{3}\times \frac{1}{8}=\frac{1}{6}x
Use the distributive property to multiply \frac{2}{3} by x+\frac{1}{8}.
\frac{2}{3}x+\frac{2\times 1}{3\times 8}=\frac{1}{6}x
Multiply \frac{2}{3} times \frac{1}{8} by multiplying numerator times numerator and denominator times denominator.
\frac{2}{3}x+\frac{2}{24}=\frac{1}{6}x
Do the multiplications in the fraction \frac{2\times 1}{3\times 8}.
\frac{2}{3}x+\frac{1}{12}=\frac{1}{6}x
Reduce the fraction \frac{2}{24} to lowest terms by extracting and canceling out 2.
\frac{2}{3}x+\frac{1}{12}-\frac{1}{6}x=0
Subtract \frac{1}{6}x from both sides.
\frac{1}{2}x+\frac{1}{12}=0
Combine \frac{2}{3}x and -\frac{1}{6}x to get \frac{1}{2}x.
\frac{1}{2}x=-\frac{1}{12}
Subtract \frac{1}{12} from both sides. Anything subtracted from zero gives its negation.
x=-\frac{1}{12}\times 2
Multiply both sides by 2, the reciprocal of \frac{1}{2}.
x=\frac{-2}{12}
Express -\frac{1}{12}\times 2 as a single fraction.
x=-\frac{1}{6}
Reduce the fraction \frac{-2}{12} to lowest terms by extracting and canceling out 2.