Solve for x
x=-2
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\frac{2}{3}\times 5x+\frac{2}{3}\times 4=\frac{1}{2}\left(3x-4\right)+1
Use the distributive property to multiply \frac{2}{3} by 5x+4.
\frac{2\times 5}{3}x+\frac{2}{3}\times 4=\frac{1}{2}\left(3x-4\right)+1
Express \frac{2}{3}\times 5 as a single fraction.
\frac{10}{3}x+\frac{2}{3}\times 4=\frac{1}{2}\left(3x-4\right)+1
Multiply 2 and 5 to get 10.
\frac{10}{3}x+\frac{2\times 4}{3}=\frac{1}{2}\left(3x-4\right)+1
Express \frac{2}{3}\times 4 as a single fraction.
\frac{10}{3}x+\frac{8}{3}=\frac{1}{2}\left(3x-4\right)+1
Multiply 2 and 4 to get 8.
\frac{10}{3}x+\frac{8}{3}=\frac{1}{2}\times 3x+\frac{1}{2}\left(-4\right)+1
Use the distributive property to multiply \frac{1}{2} by 3x-4.
\frac{10}{3}x+\frac{8}{3}=\frac{3}{2}x+\frac{1}{2}\left(-4\right)+1
Multiply \frac{1}{2} and 3 to get \frac{3}{2}.
\frac{10}{3}x+\frac{8}{3}=\frac{3}{2}x+\frac{-4}{2}+1
Multiply \frac{1}{2} and -4 to get \frac{-4}{2}.
\frac{10}{3}x+\frac{8}{3}=\frac{3}{2}x-2+1
Divide -4 by 2 to get -2.
\frac{10}{3}x+\frac{8}{3}=\frac{3}{2}x-1
Add -2 and 1 to get -1.
\frac{10}{3}x+\frac{8}{3}-\frac{3}{2}x=-1
Subtract \frac{3}{2}x from both sides.
\frac{11}{6}x+\frac{8}{3}=-1
Combine \frac{10}{3}x and -\frac{3}{2}x to get \frac{11}{6}x.
\frac{11}{6}x=-1-\frac{8}{3}
Subtract \frac{8}{3} from both sides.
\frac{11}{6}x=-\frac{3}{3}-\frac{8}{3}
Convert -1 to fraction -\frac{3}{3}.
\frac{11}{6}x=\frac{-3-8}{3}
Since -\frac{3}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{11}{6}x=-\frac{11}{3}
Subtract 8 from -3 to get -11.
x=-\frac{11}{3}\times \frac{6}{11}
Multiply both sides by \frac{6}{11}, the reciprocal of \frac{11}{6}.
x=\frac{-11\times 6}{3\times 11}
Multiply -\frac{11}{3} times \frac{6}{11} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-66}{33}
Do the multiplications in the fraction \frac{-11\times 6}{3\times 11}.
x=-2
Divide -66 by 33 to get -2.
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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