Solve 2/3(4)^3-2(4)^2-48(-4)+9=

$$\frac { 2 } { 3 } ( 4 ) ^ { 3 } - 2 ( 4 ) ^ { 2 } - 48 ( - 4 ) + 9 =$$

Evaluate

$$\frac{635}{3}\approx 211.666666667$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$\frac{2}{3}\times 64-2\times 4^{2}-48\left(-4\right)+9$$

Express \frac{2}{3}\times 64 as a single fraction.

$$\frac{2\times 64}{3}-2\times 4^{2}-48\left(-4\right)+9$$

Multiply 2 and 64 to get 128.

$$\frac{128}{3}-2\times 4^{2}-48\left(-4\right)+9$$

Calculate 4 to the power of 2 and get 16.

$$\frac{128}{3}-2\times 16-48\left(-4\right)+9$$

Multiply 2 and 16 to get 32.

$$\frac{128}{3}-32-48\left(-4\right)+9$$

Convert 32 to fraction \frac{96}{3}.

$$\frac{128}{3}-\frac{96}{3}-48\left(-4\right)+9$$

Since \frac{128}{3} and \frac{96}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{128-96}{3}-48\left(-4\right)+9$$

Subtract 96 from 128 to get 32.

$$\frac{32}{3}-48\left(-4\right)+9$$

Multiply 48 and -4 to get -192.

$$\frac{32}{3}-\left(-192\right)+9$$

The opposite of -192 is 192.

$$\frac{32}{3}+192+9$$

Convert 192 to fraction \frac{576}{3}.

$$\frac{32}{3}+\frac{576}{3}+9$$

Since \frac{32}{3} and \frac{576}{3} have the same denominator, add them by adding their numerators.

$$\frac{32+576}{3}+9$$

Add 32 and 576 to get 608.

$$\frac{608}{3}+9$$

Convert 9 to fraction \frac{27}{3}.

$$\frac{608}{3}+\frac{27}{3}$$

Since \frac{608}{3} and \frac{27}{3} have the same denominator, add them by adding their numerators.

$$\frac{608+27}{3}$$

Add 608 and 27 to get 635.

$$\frac{635}{3}$$

Factor

$$\frac{5 \cdot 127}{3} = 211\frac{2}{3} = 211.66666666666666$$