Solve 2/3(288-27div3)-4(9-6*2)^2

$$\frac { 2 } { 3 } ( 288 - 27 \div 3 ) - 4 ( 9 - 6 \times 2 ) ^ { 2 }$$

Evaluate

$$150$$

Solution Steps

Divide 27 by 3 to get 9.

$$\frac{2}{3}\left(288-9\right)-4\left(9-6\times 2\right)^{2}$$

Subtract 9 from 288 to get 279.

$$\frac{2}{3}\times 279-4\left(9-6\times 2\right)^{2}$$

Multiply \frac{2}{3} and 279 to get 186.

$$186-4\left(9-6\times 2\right)^{2}$$

Multiply 6 and 2 to get 12.

$$186-4\left(9-12\right)^{2}$$

Subtract 12 from 9 to get -3.

$$186-4\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$186-4\times 9$$

Multiply 4 and 9 to get 36.

$$186-36$$

Subtract 36 from 186 to get 150.

$$150$$

Factor

$$2\times 3\times 5^{2}$$