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\frac{2}{3}+\frac{2}{3}n=-\frac{1}{2}n
Use the distributive property to multiply \frac{2}{3} by 1+n.
\frac{2}{3}+\frac{2}{3}n+\frac{1}{2}n=0
Add \frac{1}{2}n to both sides.
\frac{2}{3}+\frac{7}{6}n=0
Combine \frac{2}{3}n and \frac{1}{2}n to get \frac{7}{6}n.
\frac{7}{6}n=-\frac{2}{3}
Subtract \frac{2}{3} from both sides. Anything subtracted from zero gives its negation.
n=-\frac{2}{3}\times \frac{6}{7}
Multiply both sides by \frac{6}{7}, the reciprocal of \frac{7}{6}.
n=\frac{-2\times 6}{3\times 7}
Multiply -\frac{2}{3} times \frac{6}{7} by multiplying numerator times numerator and denominator times denominator.
n=\frac{-12}{21}
Do the multiplications in the fraction \frac{-2\times 6}{3\times 7}.
n=-\frac{4}{7}
Reduce the fraction \frac{-12}{21} to lowest terms by extracting and canceling out 3.