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\frac{2\times 3}{3\left(1\times 3+1\right)}
Divide \frac{2}{3} by \frac{1\times 3+1}{3} by multiplying \frac{2}{3} by the reciprocal of \frac{1\times 3+1}{3}.
\frac{2}{1+3}
Cancel out 3 in both numerator and denominator.
\frac{2}{4}
Add 1 and 3 to get 4.
\frac{1}{2}
Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.