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\frac{2\left(\sqrt{11}-3\right)}{\left(\sqrt{11}+3\right)\left(\sqrt{11}-3\right)}
Rationalize the denominator of \frac{2}{\sqrt{11}+3} by multiplying numerator and denominator by \sqrt{11}-3.
\frac{2\left(\sqrt{11}-3\right)}{\left(\sqrt{11}\right)^{2}-3^{2}}
Consider \left(\sqrt{11}+3\right)\left(\sqrt{11}-3\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{2\left(\sqrt{11}-3\right)}{11-9}
Square \sqrt{11}. Square 3.
\frac{2\left(\sqrt{11}-3\right)}{2}
Subtract 9 from 11 to get 2.
\sqrt{11}-3
Cancel out 2 and 2.