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2\times 3^{\frac{1}{2}}\times 2=\frac{x}{2\sqrt{3}}
Multiply both sides of the equation by 3.
4\times 3^{\frac{1}{2}}=\frac{x}{2\sqrt{3}}
Multiply 2 and 2 to get 4.
4\times 3^{\frac{1}{2}}=\frac{x\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{x}{2\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
4\times 3^{\frac{1}{2}}=\frac{x\sqrt{3}}{2\times 3}
The square of \sqrt{3} is 3.
4\times 3^{\frac{1}{2}}=\frac{x\sqrt{3}}{6}
Multiply 2 and 3 to get 6.
\frac{x\sqrt{3}}{6}=4\times 3^{\frac{1}{2}}
Swap sides so that all variable terms are on the left hand side.
x\sqrt{3}=24\times 3^{\frac{1}{2}}
Multiply both sides of the equation by 6.
\sqrt{3}x=24\sqrt{3}
Reorder the terms.
\frac{\sqrt{3}x}{\sqrt{3}}=\frac{24\sqrt{3}}{\sqrt{3}}
Divide both sides by \sqrt{3}.
x=\frac{24\sqrt{3}}{\sqrt{3}}
Dividing by \sqrt{3} undoes the multiplication by \sqrt{3}.
x=24
Divide 24\sqrt{3} by \sqrt{3}.