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\frac{\frac{2}{3}\sqrt{3}}{1+\left(\frac{1}{3}\sqrt{3}\right)^{2}}
Multiply 2 and \frac{1}{3} to get \frac{2}{3}.
\frac{\frac{2}{3}\sqrt{3}}{1+\left(\frac{1}{3}\right)^{2}\left(\sqrt{3}\right)^{2}}
Expand \left(\frac{1}{3}\sqrt{3}\right)^{2}.
\frac{\frac{2}{3}\sqrt{3}}{1+\frac{1}{9}\left(\sqrt{3}\right)^{2}}
Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.
\frac{\frac{2}{3}\sqrt{3}}{1+\frac{1}{9}\times 3}
The square of \sqrt{3} is 3.
\frac{\frac{2}{3}\sqrt{3}}{1+\frac{1}{3}}
Multiply \frac{1}{9} and 3 to get \frac{1}{3}.
\frac{\frac{2}{3}\sqrt{3}}{\frac{4}{3}}
Add 1 and \frac{1}{3} to get \frac{4}{3}.
\frac{\frac{2}{3}\sqrt{3}\times 3}{4}
Divide \frac{2}{3}\sqrt{3} by \frac{4}{3} by multiplying \frac{2}{3}\sqrt{3} by the reciprocal of \frac{4}{3}.
\frac{2\sqrt{3}}{4}
Multiply \frac{2}{3} and 3 to get 2.
\frac{1}{2}\sqrt{3}
Divide 2\sqrt{3} by 4 to get \frac{1}{2}\sqrt{3}.