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\frac{2\times 3\sqrt{6}+8\sqrt{6}}{6\sqrt{12}-5\sqrt{3}}
Factor 54=3^{2}\times 6. Rewrite the square root of the product \sqrt{3^{2}\times 6} as the product of square roots \sqrt{3^{2}}\sqrt{6}. Take the square root of 3^{2}.
\frac{6\sqrt{6}+8\sqrt{6}}{6\sqrt{12}-5\sqrt{3}}
Multiply 2 and 3 to get 6.
\frac{14\sqrt{6}}{6\sqrt{12}-5\sqrt{3}}
Combine 6\sqrt{6} and 8\sqrt{6} to get 14\sqrt{6}.
\frac{14\sqrt{6}}{6\times 2\sqrt{3}-5\sqrt{3}}
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
\frac{14\sqrt{6}}{12\sqrt{3}-5\sqrt{3}}
Multiply 6 and 2 to get 12.
\frac{14\sqrt{6}}{7\sqrt{3}}
Combine 12\sqrt{3} and -5\sqrt{3} to get 7\sqrt{3}.
\frac{2\sqrt{6}}{\sqrt{3}}
Cancel out 7 in both numerator and denominator.
\frac{2\sqrt{6}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{2\sqrt{6}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{2\sqrt{6}\sqrt{3}}{3}
The square of \sqrt{3} is 3.
\frac{2\sqrt{3}\sqrt{2}\sqrt{3}}{3}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
\frac{2\times 3\sqrt{2}}{3}
Multiply \sqrt{3} and \sqrt{3} to get 3.
2\sqrt{2}
Cancel out 3 and 3.