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\frac{2\times 3\sqrt{6}+4\sqrt{6}}{4\sqrt{8}-3\sqrt{2}}
Factor 54=3^{2}\times 6. Rewrite the square root of the product \sqrt{3^{2}\times 6} as the product of square roots \sqrt{3^{2}}\sqrt{6}. Take the square root of 3^{2}.
\frac{6\sqrt{6}+4\sqrt{6}}{4\sqrt{8}-3\sqrt{2}}
Multiply 2 and 3 to get 6.
\frac{10\sqrt{6}}{4\sqrt{8}-3\sqrt{2}}
Combine 6\sqrt{6} and 4\sqrt{6} to get 10\sqrt{6}.
\frac{10\sqrt{6}}{4\times 2\sqrt{2}-3\sqrt{2}}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\frac{10\sqrt{6}}{8\sqrt{2}-3\sqrt{2}}
Multiply 4 and 2 to get 8.
\frac{10\sqrt{6}}{5\sqrt{2}}
Combine 8\sqrt{2} and -3\sqrt{2} to get 5\sqrt{2}.
\frac{2\sqrt{6}}{\sqrt{2}}
Cancel out 5 in both numerator and denominator.
\frac{2\sqrt{6}\sqrt{2}}{\left(\sqrt{2}\right)^{2}}
Rationalize the denominator of \frac{2\sqrt{6}}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{2\sqrt{6}\sqrt{2}}{2}
The square of \sqrt{2} is 2.
\frac{2\sqrt{2}\sqrt{3}\sqrt{2}}{2}
Factor 6=2\times 3. Rewrite the square root of the product \sqrt{2\times 3} as the product of square roots \sqrt{2}\sqrt{3}.
\frac{2\times 2\sqrt{3}}{2}
Multiply \sqrt{2} and \sqrt{2} to get 2.
2\sqrt{3}
Cancel out 2 and 2.