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\frac{2\sqrt{3}\sqrt{6}}{3\left(\sqrt{6}\right)^{2}}
Rationalize the denominator of \frac{2\sqrt{3}}{3\sqrt{6}} by multiplying numerator and denominator by \sqrt{6}.
\frac{2\sqrt{3}\sqrt{6}}{3\times 6}
The square of \sqrt{6} is 6.
\frac{2\sqrt{3}\sqrt{3}\sqrt{2}}{3\times 6}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
\frac{2\times 3\sqrt{2}}{3\times 6}
Multiply \sqrt{3} and \sqrt{3} to get 3.
\frac{2\times 3\sqrt{2}}{18}
Multiply 3 and 6 to get 18.
\frac{6\sqrt{2}}{18}
Multiply 2 and 3 to get 6.
\frac{1}{3}\sqrt{2}
Divide 6\sqrt{2} by 18 to get \frac{1}{3}\sqrt{2}.