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\frac{2\times 3\sqrt{3}-4\sqrt{3}+\sqrt{12}}{\sqrt{75}+\sqrt{48}-8\sqrt{3}}
Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.
\frac{6\sqrt{3}-4\sqrt{3}+\sqrt{12}}{\sqrt{75}+\sqrt{48}-8\sqrt{3}}
Multiply 2 and 3 to get 6.
\frac{2\sqrt{3}+\sqrt{12}}{\sqrt{75}+\sqrt{48}-8\sqrt{3}}
Combine 6\sqrt{3} and -4\sqrt{3} to get 2\sqrt{3}.
\frac{2\sqrt{3}+2\sqrt{3}}{\sqrt{75}+\sqrt{48}-8\sqrt{3}}
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
\frac{4\sqrt{3}}{\sqrt{75}+\sqrt{48}-8\sqrt{3}}
Combine 2\sqrt{3} and 2\sqrt{3} to get 4\sqrt{3}.
\frac{4\sqrt{3}}{5\sqrt{3}+\sqrt{48}-8\sqrt{3}}
Factor 75=5^{2}\times 3. Rewrite the square root of the product \sqrt{5^{2}\times 3} as the product of square roots \sqrt{5^{2}}\sqrt{3}. Take the square root of 5^{2}.
\frac{4\sqrt{3}}{5\sqrt{3}+4\sqrt{3}-8\sqrt{3}}
Factor 48=4^{2}\times 3. Rewrite the square root of the product \sqrt{4^{2}\times 3} as the product of square roots \sqrt{4^{2}}\sqrt{3}. Take the square root of 4^{2}.
\frac{4\sqrt{3}}{9\sqrt{3}-8\sqrt{3}}
Combine 5\sqrt{3} and 4\sqrt{3} to get 9\sqrt{3}.
\frac{4\sqrt{3}}{\sqrt{3}}
Combine 9\sqrt{3} and -8\sqrt{3} to get \sqrt{3}.
\frac{4\sqrt{3}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{4\sqrt{3}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{4\sqrt{3}\sqrt{3}}{3}
The square of \sqrt{3} is 3.
\frac{4\times 3}{3}
Multiply \sqrt{3} and \sqrt{3} to get 3.
\frac{12}{3}
Multiply 4 and 3 to get 12.
4
Divide 12 by 3 to get 4.