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\frac{2}{3}x\times 3^{\frac{1}{2}}\times 2\sqrt{2}=2\sqrt{3}
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
\frac{2\times 2}{3}x\times 3^{\frac{1}{2}}\sqrt{2}=2\sqrt{3}
Express \frac{2}{3}\times 2 as a single fraction.
\frac{4}{3}x\times 3^{\frac{1}{2}}\sqrt{2}=2\sqrt{3}
Multiply 2 and 2 to get 4.
\frac{4}{3}\sqrt{2}\sqrt{3}x=2\sqrt{3}
Reorder the terms.
\frac{4}{3}\sqrt{6}x=2\sqrt{3}
To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.
\frac{4\sqrt{6}}{3}x=2\sqrt{3}
The equation is in standard form.
\frac{3\times \frac{4\sqrt{6}}{3}x}{4\sqrt{6}}=\frac{3\times 2\sqrt{3}}{4\sqrt{6}}
Divide both sides by \frac{4}{3}\sqrt{6}.
x=\frac{3\times 2\sqrt{3}}{4\sqrt{6}}
Dividing by \frac{4}{3}\sqrt{6} undoes the multiplication by \frac{4}{3}\sqrt{6}.
x=\frac{3\sqrt{2}}{4}
Divide 2\sqrt{3} by \frac{4}{3}\sqrt{6}.