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\frac{\left(2\sqrt{2}+3\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right)}{\left(\sqrt{2}+\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right)}
Rationalize the denominator of \frac{2\sqrt{2}+3\sqrt{3}}{\sqrt{2}+\sqrt{3}} by multiplying numerator and denominator by \sqrt{2}-\sqrt{3}.
\frac{\left(2\sqrt{2}+3\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right)}{\left(\sqrt{2}\right)^{2}-\left(\sqrt{3}\right)^{2}}
Consider \left(\sqrt{2}+\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(2\sqrt{2}+3\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right)}{2-3}
Square \sqrt{2}. Square \sqrt{3}.
\frac{\left(2\sqrt{2}+3\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right)}{-1}
Subtract 3 from 2 to get -1.
-\left(2\sqrt{2}+3\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right)
Anything divided by -1 gives its opposite.
-\left(2\left(\sqrt{2}\right)^{2}-2\sqrt{3}\sqrt{2}+3\sqrt{3}\sqrt{2}-3\left(\sqrt{3}\right)^{2}\right)
Apply the distributive property by multiplying each term of 2\sqrt{2}+3\sqrt{3} by each term of \sqrt{2}-\sqrt{3}.
-\left(2\times 2-2\sqrt{3}\sqrt{2}+3\sqrt{3}\sqrt{2}-3\left(\sqrt{3}\right)^{2}\right)
The square of \sqrt{2} is 2.
-\left(4-2\sqrt{3}\sqrt{2}+3\sqrt{3}\sqrt{2}-3\left(\sqrt{3}\right)^{2}\right)
Multiply 2 and 2 to get 4.
-\left(4-2\sqrt{6}+3\sqrt{3}\sqrt{2}-3\left(\sqrt{3}\right)^{2}\right)
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.
-\left(4-2\sqrt{6}+3\sqrt{6}-3\left(\sqrt{3}\right)^{2}\right)
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.
-\left(4+\sqrt{6}-3\left(\sqrt{3}\right)^{2}\right)
Combine -2\sqrt{6} and 3\sqrt{6} to get \sqrt{6}.
-\left(4+\sqrt{6}-3\times 3\right)
The square of \sqrt{3} is 3.
-\left(4+\sqrt{6}-9\right)
Multiply -3 and 3 to get -9.
-\left(-5+\sqrt{6}\right)
Subtract 9 from 4 to get -5.
-\left(-5\right)-\sqrt{6}
To find the opposite of -5+\sqrt{6}, find the opposite of each term.
5-\sqrt{6}
The opposite of -5 is 5.